MHB Is the Calculation for Eb6 Displacement Correct?

  • Thread starter Thread starter karush
  • Start date Start date
  • Tags Tags
    Displacement
AI Thread Summary
The discussion focuses on the calculation for EB6 displacement, highlighting two main errors. First, the angle for the final leg should be adjusted to 217° based on the starting angle of 0° from the eastward direction. Second, there is a mistake in the calculation of the y-component, where C_x was mistakenly repeated instead of calculating C_y. A participant acknowledges the error regarding C_x but questions the interpretation of "due east" as simply heading east. The conversation emphasizes the importance of accurate angle measurements and component calculations in displacement problems.
karush
Gold Member
MHB
Messages
3,240
Reaction score
5
View attachment 7676

ok this is due 011418

I think its correct but suggestions
didn't know the best format for this
 

Attachments

  • eb6.PNG
    eb6.PNG
    21.2 KB · Views: 138
Mathematics news on Phys.org
Two things wrong.

First, the angle for the final leg. If the angle for the first leg is $0^\circ$, that means you are starting angle measurements from the eastward direction. So the angle for the third leg is $270^\circ - 53^\circ = 217^\circ$.

Second, for the $y$-component of the final leg you have repeated $C_x$ instead of calculating $C_y$.
 
ok i see the c_x error
but isn't due east mean heading east?
 
$\sqrt{(620+(220\sqrt{2})+(-264))^2+(0+(-220\sqrt{2})+(-264))^2}\approx881 \, km$

hopefully
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
Back
Top