Is the Calculation for Eb6 Displacement Correct?

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Discussion Overview

The discussion revolves around the correctness of a calculation related to the displacement for a problem labeled Eb6. Participants are examining the mathematical details of the calculation, including angle measurements and component calculations, within a technical context.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant expresses confidence in the correctness of the calculation but invites suggestions for improvement.
  • Another participant identifies two errors: the angle for the final leg of the displacement and the incorrect use of the $C_x$ component instead of calculating $C_y$.
  • A different participant questions the interpretation of "due east" in relation to angle measurements.
  • A later reply provides a calculation for the overall displacement using a specific formula, presenting an approximate result of 881 km.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus, as there are multiple competing views regarding the correctness of the calculation and the interpretation of angles.

Contextual Notes

Limitations include potential misunderstandings of angle definitions and the reliance on specific component calculations that may not have been fully resolved.

karush
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View attachment 7676

ok this is due 011418

I think its correct but suggestions
didn't know the best format for this
 

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Two things wrong.

First, the angle for the final leg. If the angle for the first leg is $0^\circ$, that means you are starting angle measurements from the eastward direction. So the angle for the third leg is $270^\circ - 53^\circ = 217^\circ$.

Second, for the $y$-component of the final leg you have repeated $C_x$ instead of calculating $C_y$.
 
ok i see the c_x error
but isn't due east mean heading east?
 
$\sqrt{(620+(220\sqrt{2})+(-264))^2+(0+(-220\sqrt{2})+(-264))^2}\approx881 \, km$

hopefully
 

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