Is the Calculation of $(3 \diamond 8) \square 2 = 1940$ Correct?

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karush
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define the binary operater $\diamond$ by
$a\diamond b$=4a+4b
and $s\square b$ by $a\square b=a^2+b^2$
find
$(3\diamond 8)\square 2=
[(4(3)+4(8))^2 +2^2]=1940$
ok just want to see if this is correct
before i run thru the ribbon :unsure:
 
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