Is the Calculation of the Bird's Average Acceleration Correct?

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Homework Help Overview

The discussion revolves around calculating the average acceleration of a bird flying between two positions, incorporating vector components of velocity and time. The problem involves kinematics and vector analysis.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the calculation of average acceleration using initial and final velocity components, questioning the correctness of signs and directional assumptions in their calculations.

Discussion Status

Some participants have provided feedback on the calculations, suggesting re-evaluation of velocity signs and confirming the positive direction for the y-axis. There is an ongoing exploration of different interpretations of the results.

Contextual Notes

Participants are considering the implications of sign conventions and directional definitions in their calculations, which may affect the final results. There is uncertainty regarding the correctness of the average acceleration derived from the calculations.

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Physics question, solved but need clarification!

Homework Statement


A bird take 8.5 s to fly from position A to position B. Determine the bird's avg acceleration
Vb = 7.8 m/s [25 degrees N of E]
Va = 4.4 m/s [ 31 degrees S of E]


Homework Equations


Vax/Va = cos31
Vax/4.4 m/s = cos31
3.8 m/s

Vay/Va = sin31
Vay/4.4 m/s = sin31
2.3 m/s

Vbx/Vb = cos25
Vbx = 7.8cos25
7.1m/s

Vby/Vb = sin25
Vby= 7.8sin25
3.3m/s

Ay = Vby- Vay / t
3.3-2.3/ 8.5 s
0.12 m/s^2

Ax = Vbx- Vax / t
7.1 m/s - 3.8 m/s / 8.5 s
0.4 m/s^2

a^2 = Ax^2 + Ay^2
0.16 + 0.0144
0.174 m/s^2 and then you square root it 0.41 m/s^2

tantheta = Ay/Ax
0.12 m/s^2/0.4 m/s^2
0.3 = 17 degrees

The Attempt at a Solution



The bird's avg acceleration is 0.41 m/s^2 [17 degrees N of E]

I just need to make sure if I did this right, if anyone would clarify this that would be great!
thanks
 
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Welcome to PF :smile:

It's mostly correct. You'll want to recheck +/- signs for the velocities. Is Northward or Southward the "positive y" direction?
 


oo then if I messed up on the signs I guess my answer is wrong, and northward is the positive y direction I think
 


Vax/Va = cos31
Vax/4.4 m/s = cos31
3.8 m/s

Vay/Va = sin31
Vay/4.4 m/s = sin31
- 2.3 m/s

Vbx/Vb = cos25
Vbx = 7.8cos25
7.1m/s

Vby/Vb = sin25
Vby= 7.8sin25
3.3m/s

Ay = Vby- Vay / t
3.3 + 2.3/ 8.5 s
0.7 m/s^2

Ax = Vbx- Vax / t
7.1 m/s - 3.8 m/s / 8.5 s
0.4 m/s^2

a^2 = Ax^2 + Ay^2
0.16 + 0.49
0.65 m/s^2 and then you square root it 0.8 m/s^2

tantheta = Ay/Ax
0.7m/s^2/0.4 m/s^2
1.75 = 60 degrees

the bird's avg acceleration is 0.8 m/s^2 [60 degrees N of E]

is this right? :S
I used the signs for the velocities but not quite sure if I did it right...
 


Looks good. :smile:
 

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