How Do You Calculate a Bird's Average Acceleration?

Click For Summary
SUMMARY

The average acceleration of a bird flying from position A to position B over 8.5 seconds is calculated to be 1.07 m/s² at an angle of 60.4 degrees North of East. The initial velocity (va) is 4.4 m/s at 3 degrees South of East, while the final velocity (vb) is 7.8 m/s at 25 degrees North of East. The acceleration components were initially miscalculated, with the corrected values being ax = 0.314733 m/s² and ay = 0.360723 m/s². Proper application of the equations for average acceleration is crucial for accurate results.

PREREQUISITES
  • Understanding of vector components in physics
  • Familiarity with kinematic equations
  • Knowledge of trigonometric functions, particularly tangent
  • Basic skills in unit conversion and dimensional analysis
NEXT STEPS
  • Review kinematic equations for two-dimensional motion
  • Study vector addition and decomposition techniques
  • Learn about the significance of angles in vector calculations
  • Explore practical applications of average acceleration in real-world scenarios
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in understanding motion and acceleration in a two-dimensional context.

christinaa_s
Messages
15
Reaction score
0
QUESTION=
a bird takes 8.5 s to fly from position A to position B along the path. determine the bird's average acceleration.

va= 4.4 m/s (3 degrees S of E) -- is this the initial velocity?
vb= 7.8 m/s ( 25 degrees N of E) -- is this the final velocity?

THIS IS WHAT I GOT SO FAR, I"M NOT SURE IF IT IS RIGHT AT ALL -->

ay = vfy - vfi / time

i found , ax = 0.52
ay = 0.92

a(2) = ax(2) + ay(2)
= (0.52)2 + (0.92)2
= 0.29 + 0.85
= √1.14 m/s(2)
therefore, average acceleration = 1.07 m/s


tan = 0.92 \ 0.52
tan = 60.4 degrees

Therefore the average acceleration of the car is 1.07 m/s (60.4 degreesN of E)
 
Physics news on Phys.org
christinaa_s said:
QUESTION=
a bird takes 8.5 s to fly from position A to position B along the path. determine the bird's average acceleration.

va= 4.4 m/s (3 degrees S of E) -- is this the initial velocity?
vb= 7.8 m/s ( 25 degrees N of E) -- is this the final velocity?

THIS IS WHAT I GOT SO FAR, I"M NOT SURE IF IT IS RIGHT AT ALL -->

ay = vfy - vfi / time

i found , ax = 0.52
ay = 0.92

a(2) = ax(2) + ay(2)
= (0.52)2 + (0.92)2
= 0.29 + 0.85
= √1.14 m/s(2)
therefore, average acceleration = 1.07 m/s


tan = 0.92 \ 0.52
tan = 60.4 degrees

Therefore the average acceleration of the car is 1.07 m/s (60.4 degreesN of E)

Just a quick comment: You somehow got your acceleration components wrong. I get ax = 0.314733 /s^2 and ay = 0.360723 m/s^2. (That's with E being the +x and N being the +y.) Perhaps you should show how you are putting the numbers into the equations.

-Dan
 

Similar threads

Replies
14
Views
2K
  • · Replies 13 ·
Replies
13
Views
7K
  • · Replies 33 ·
2
Replies
33
Views
6K
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
6K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
4
Views
2K