Is the Cartesian product ℝ × ℝ² equal to ℝ² × ℝ and ℝ³?

  • Level: Graduate 
  • Thread starter Thread starter quasar987
  • Start date Start date
  • Tags Tags
    Cartesian Product
Join the discussion
Registration is free. Start your own thread to ask a follow-up.
7 replies · 4K views
Science Advisor
Homework Helper
Gold Member
Messages
4,796
Reaction score
32
Is it true that

[tex]\mathbb{R}\times \mathbb{R}^2 = \mathbb{R}^2 \times \mathbb{R} = \mathbb{R}^3[/tex]

?
 
Physics news on Phys.org
Wouldn't the elements of [tex]\mathbb{R}\times\mathbb{R}^2[/tex] all be of the form (a, (b, c)) whereas the elements of [tex]\mathbb{R}^2\times\mathbb{R}[/tex] all be of the form ((a, b), c)?
 
(Assuming you meant the 2 to have precedence over the x)
 
It's so unimportant, I didn't feel the need to elaborate on it in my response. :biggrin:

In the strictest sense, they aren't equal, but I don't think I've ever really seen anyone distinguish between them.
 
Strictly speaking they are isomorphic not equal, however the isomoprphism is fairly 'canonical' and in general there are canonical isomorphisms between Ax(BxC) and (AxB)xC, and we will by commonly accepted abuse of notation refer to it as AxBxC.

This is one of the "modern" ways of saying it in the lagauge of category theory.