Is the Converse of the Given Statement True for Any Positive Integer n?

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Discussion Overview

The discussion revolves around the properties of integers related to perfect squares and prime numbers. Participants explore whether the statement that if \( n \) is a prime number, then \( a = m - n \) is not a perfect square, holds true, and whether the converse is valid for any integer \( n \). The scope includes mathematical reasoning and exploration of examples.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • Some participants propose that if \( n \) is a prime number greater than 2, then \( a = m - n \) is not a perfect square, where \( m \) is the smallest perfect square greater than or equal to \( n \).
  • Examples are provided, such as for \( n = 3 \) and \( n = 5 \), where \( a \) results in perfect squares (1 and 4, respectively).
  • Another participant argues that the converse may not hold, citing \( n = 6 \) as a counterexample where \( a = 3 \) is not a perfect square.
  • Concerns are raised about the interpretation of the conditions, specifically regarding the requirement that \( m \) cannot be less than \( n \).
  • Clarifications are sought regarding the notation used, particularly the reference to 'N' instead of 'n'.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the validity of the original statement or its converse. Multiple competing views remain, with some examples supporting one side and others challenging it.

Contextual Notes

There are unresolved assumptions regarding the definitions of \( m \) and \( n \), and the implications of the examples provided. The discussion highlights the need for clarity in the conditions set forth in the original question.

johnny009
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if n is a positive integer greater than 2 and m the smallest integer greater than or = n, that is a perfect square.
Let a = m-n.

Show that if n is prime, then a is not a perfect square.

Also, is the converse of above true, for any integer n?

any guidance, will be much appreciated?

Thanks
 
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johnny009 said:
if n is a positive integer greater than 2 and m the smallest integer greater than or = n, that is a perfect square.
Let a = m-n.

Show that if n is prime, then a is not a perfect square.

Also, is the converse of above true, for any integer n?
any guidance, will be much appreciated?Thanks

Hey johnny009! Welcome to MHB! (Smile)Guidance: let's try a couple of examples, starting with the simplest we can think of.The smallest prime $n$ is $3$, in which case $m=2^2=4$, and $a=4-3=1$, which is a perfect square!
Ah well, maybe $a=1$ is a special case...

Let's try again, the next prime $n$ is $5$, so that $m=3^2=9$, and $a=9-5=4$, which is again a perfect square!

Erm... I think it's not true, and we have 2 counter examples to prove it.Continuing with $n=6$, we get $m=3^2=9$, and $a=9-6=3$, which is not a perfect square... and $n$ is not prime.
So we have a counter example for the converse as well.
 
I like Serena said:
Hey johnny009! Welcome to MHB! (Smile)Guidance: let's try a couple of examples, starting with the simplest we can think of.The smallest prime $n$ is $3$, in which case $m=2^2=4$, and $a=4-3=1$, which is a perfect square!
Ah well, maybe $a=1$ is a special case...

Let's try again, the next prime $n$ is $5$, so that $m=3^2=9$, and $a=9-5=4$, which is again a perfect square!

Erm... I think it's not true, and we have 2 counter examples to prove it.Continuing with $n=6$, we get $m=3^2=9$, and $a=9-6=3$, which is not a perfect square... and $n$ is not prime.
So we have a counter example for the converse as well.
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Hi There,

Thanks a lot for the reply.

But, your solutions ignores the fact, that 'm' cannot be less than 'N' ...as per the QUESTION??

So, your solution...is not really addressing the Question.

CHEERS

John.
 
johnny009 said:
---------------------------------------------------------------------------------------------

Hi There,

Thanks a lot for the reply.

But, your solutions ignores the fact, that 'm' cannot be less than 'N' ........as per the QUESTION??

So, your solution...is not really addressing the Question.

CHEERS

John.

I'm assuming you mean 'n' instead of 'N', since there is no reference to 'N'?
Erm... in each of the examples $m\ge n$ as per the question... am I missing something? (Wondering)
 

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