Is the Derivative the Same as the Slope of a Function?

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SUMMARY

The derivative of a function is indeed the slope of the tangent line at any given point on that function. For instance, for the function f(x) = x², the derivative f'(x) = 2x provides the slope at any point x. Evaluating this at x = 3 yields a slope of 6 at the point (3, 9). Additionally, when applying the chain rule to complex functions like y = x⁴sin(x)cos(x), the product rule is necessary, as the chain rule does not apply directly in this case.

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Homework Statement



is the derivativethe same thing as the slope of the function for which we're finding the derivative?

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The Attempt at a Solution

 
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Jan Hill said:

Homework Statement


is the derivativethe same thing as the slope of the function for which we're finding the derivative?
For a given function (assumed to be differentiable), the derivative is another function that gives the slope of the tangent line at an arbitrary point on the given function.

For example, if f(x) = x2, the derivative function is f'(x) = 2x.

If you evaluate f' at say, x = 3, you get the slope of the tangent line to the graph of f(x) = x2 at the point (3, 9). Since f'(3) = 2*3 = 6, the slope of the tangent line is 6 at the point (3, 9) on the graph of y = x2.
 
chain rule

How do I apply the chain rule to y = x^4sinxcosx in finding the derivative since there are really 3 distinct parts to it.
 
The chain rule doesn't apply in this problem. Use the product rule.
d/dx(x4sin(x)cos(x)) = d/dx(x4) * sin(x)cos(x) + x4 * d/dx(sin(x)) * cos(x) + x4 * sin(x) * d/dx(cos(x))
 
Thank you
 

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