MHB Is the inequality correctly solved by multiplying each fraction by 100?

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The inequality (9/10) < (3x - 1)/-2 < 91/100 can be approached by multiplying each fraction by 100, which maintains the direction of the inequalities since 100 is positive. However, the negative sign in the denominator complicates the process, leading to the transformation 90 < -50(3x - 1) < 91. This simplifies to 90 < -150x + 50 < 91, which further reduces to -90/150 > x > -41/150. The final solution indicates that x must be less than -3/5 and greater than -41/150, confirming the inequality is correctly solved.
mathdad
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Solve the inequality.

(9/10) < (3x - 1)/-2 < 91/100

Do I start by multiplying each fraction by 100?
 
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That would be one reasonable way of starting. As is so often the case, you can, you don't have to. And, since 100 is positive, multiplying by 100 does not change the direction of the inequalities: 90< -50(3x- 1)< 91.

But that "-" in the "-2" is going to cause problems!
 
90< -50(3x- 1)< 91

90 < -150x + 50 < 91

90 < -150x < 91 - 50

90 < -150x < 41

-90/150 > x > -41/150

-3/5 > x > -41/150

Correct?
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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