- #1

Yankel

- 395

- 0

I am trying to solve this inequality:

\[\frac{2}{x^{2}-1}\leq \frac{1}{x+1}\]

I've tried several things, from multiplying both sides by

\[(x^{2}-1)^{2}\]

finding the common denominator, but didn't get the correct answer, which is:

\[2<x<3\]

or

\[x<-1\]How to you solve this one ?