Is the Joule-Thompson experiment an isenthalpic process?

  • Thread starter Thread starter zeshkani
  • Start date Start date
  • Tags Tags
    Experiment
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
5 replies · 7K views
zeshkani
Messages
28
Reaction score
0

Homework Statement



Show that the Joule-Thompson experiment is an isenthalpic process. (ΔH=0). The experimentally determined quantity is (Partial derivative T)/(Partial derivative P)H . Starting with the total differential for H, show that:

(Partial deriv H)/(Partial deriv P)T = - Cp(Partial deriv T)/(Partial deriv P)H

does anybody know even where to start ??, iam just confused with this question
 
Physics news on Phys.org
Do you know what the total differential of H is?
 
no i dont, since i never took calc 3 and still having some hard time partial derivatives
 
The total differential of H is:

[tex]dH=C_p dT+ \left[ v - T \left( \frac{\partial v}{\partial T} \right) _p \right] dp[/tex]
 
Last edited:
those this even seem right ??
 

Attachments

  • 1321.jpg
    1321.jpg
    16.3 KB · Views: 483
If its isoenthalpic the dH is going to be zero. You're almost there.