Is the Locus of Point P a Hyperbola When Area OMPN is Constant?

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SUMMARY

The discussion centers on proving that the locus of point P, from which perpendiculars PM and PN are drawn to two fixed lines OM and ON, forms a hyperbola when the area OMPN remains constant. The lines are defined with OM as the y-axis and ON as y = mx. By determining the coordinates of point P as (x_0, y_0) and calculating the area of the triangle formed, the relationship between x_0 and y_0 can be established, confirming the hyperbolic nature of the locus.

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Homework Statement


From a point P, perpendiculars PM and PN are drawn to two fixed straight lines OM and ON. If the area OMPN, be constant, prove that the locus of P is a hyperbola.


How do we start?
 
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You can, without loss of generality, assume that one line, say OM, is the y-axis, and the other, ON, is given by y= mx for some number m. If P has coordinates [itex](x_0, y_0)[/itex] then the perpendicular to OM is the line [itex]y= y_0[/itex]. The line through P perpendicular to ON is given by [itex]y= -(1/m)(x- x_0)+ y_0[/itex]. You can find its length by finding x such that [itex]y= -(1/m)(x- x_0)+ y_0= mx[/itex], where the two lines cross. Find the area of that figure, as a function of [itex]x_0[/itex] and [itex]y_0[/itex], set it equal to a constant, and see what relation you get between [itex]x_0[/itex] and [itex]y_0[/itex].
 
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