Is the Official Google Answer to this Controversial Interview Question Correct?

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SUMMARY

The discussion centers on a controversial Google interview question regarding the expected fraction of female births in a country where couples continue having children until they have a boy. The consensus among participants is that the official Google answer of 0.5 is correct, as the probability of each birth being male or female remains 50%. However, some argue that this does not accurately reflect the overall population distribution of genders due to the stopping rule employed by families. The debate highlights the distinction between the average fraction of girls per family and the overall fraction of girls in the population.

PREREQUISITES
  • Understanding of probability theory and basic statistics
  • Familiarity with concepts of expected value and population distribution
  • Knowledge of the stopping rule in probability scenarios
  • Basic algebraic manipulation skills for probability calculations
NEXT STEPS
  • Research "expected value in probability" to deepen understanding of statistical expectations
  • Explore "Simpson's paradox" and its implications in statistical reasoning
  • Study "stopping rules in probability" and their effects on outcomes
  • Examine "population dynamics in probability models" for insights into gender ratios
USEFUL FOR

Mathematicians, statisticians, data scientists, and anyone involved in probability theory or gender studies will benefit from this discussion.

  • #31
So DH are you saying, if I take up the bet with him.

a) I would expect to win if I call him on his maths- as the only answer- even in this restricted sense is 0.5

b) I would expect to win if I call him on his interpretation of the problem.

He is offering a quite substantial bet on both options.
 
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  • #32
You should expect to lose if you take him up on his terms. He has redefined the problem to be something other than that asked by the question. In other words, he is cheating.

Cheating, by the way, is yet another way to make a martingale have an outcome that differs from what probability theory says it should be.
 
  • #33
Thanks DH

But he says he is willing to make a bet to show that most stats professors will define/interpret the puzzle in the way that he has.

From discussions on here, would you not say I would have more than evens chance of winning
 
  • #34
I really don't want to get involved in and I don't really care about this imbroglio. Some supposedly brilliant scientist is wrong and is strong-headedly digging himself a grave about being right. So what else is new? Have at it if you do.
 
  • #35
If you want to make a bet with him, make a bet with him. But this is starting to turn into "but he said so!".

Let me also point out again that this same argument applies to lottery tickets. I wouldn't try to get $15,000 out of my colleagues, where it's dependent on interpretation. I'd just get it out of the state lottery office, where they cannot argue about whether you are holding a winning ticket.
 
  • #36
Thanks Guys. Your contributions have been very helpful.

As Vanadium suggests, it does look like a martingale.
 
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