Is the Poisson Sum Formula Equivalent to the Integral of a Function?

[lokofer]

If we have (Poisson sum formula) in the form:

\sum_{n=-\infty}^{\infty}f(n)= \int_{-\infty}^{\infty}dx f(x) \omega (x)

with \omega (x) = \sum_{n=-\infty}^{\infty}e^{2i \pi nx}

Then my question is if we would have that:

\sum_{n=-\infty}^{\infty} \frac{ f(n)}{ \omega (n)} = \int_{-\infty}^{\infty} dx f(x) ??

 

[shmoe]

You should stop and ask if:

\omega (x) = \sum_{n=-\infty}^{\infty}e^{2i \pi nx}

makes any sense at all. You have an infinite sum and the terms aren't tending to zero.