Is the product rule on operators different from traditional calculus?

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SUMMARY

The discussion centers on the application of the product rule for non-commuting operators in calculus, specifically for operators denoted as \Psi and \Phi. The participants confirm that the product rule can be expressed as $$\nabla (\Phi \Psi) = \Psi (\nabla \Phi) + \Phi (\nabla \Psi)$$, emphasizing the importance of maintaining the original order of operators. Additionally, they clarify that if Ψ equals the gradient operator ∇, then the expression ∇Ψ must be defined accordingly. This highlights the nuances in operator calculus compared to traditional calculus.

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Abigale
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Hey Guys,

I regard two operators \Psi , \Phi, that don't commute.

Does the product-rule, looks like that?

$$\nabla (\Phi \Psi)

= \Psi (\nabla \Phi)

+\Phi (\nabla \Psi)

$$

THX
 
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How do you define the different items in this equation?
For example if Ψ = ∇, how do you define ∇Ψ ?
And in general?
 
Abigale said:
Does the product-rule, looks like that?
$$\nabla (\Phi \Psi) = \Psi (\nabla \Phi) +\Phi (\nabla \Psi) $$
You need to keep the original order:

$$\nabla (\Phi \Psi) = (\nabla \Phi) \Psi+\Phi (\nabla \Psi) $$
 

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