Is the Rydberg formula true for electron absorption only?

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SUMMARY

The Rydberg formula applies to both electron absorption and emission processes in hydrogen. When an electron transitions from a higher energy state (n=3) to a lower energy state (n=1), the energy difference can be expressed as ΔE = E1 - E3. This manipulation leads to the same Rydberg formula, 1/λ = R (1/nf² - 1/ni²), confirming that the wavelengths of light emitted during electron transitions to lower states are identical to those absorbed during transitions to higher states.

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  • Knowledge of energy levels in hydrogen
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Students of physics, educators teaching quantum mechanics, and researchers in atomic spectroscopy will benefit from this discussion on the Rydberg formula and electron transitions.

Fibi
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Since we know that when an electron goes from the ground state (hydrogen) n=1 to n=3 for example, we have
ΔE = E3 - E1
by manipulating the equation we get Rydberg's formula
1/λ= R (1/ni2 - 1/nf2) (where R is Rydberg's constant)

My question here, if the electron goes from higher energy state to a lower energy state, let's say from n=3 to n=1 then :
ΔE = E1 - E3

Can we manipulate this to get :
1/λ= R (1/nf2 - 1/ni2)
 
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Yes, the same wavelengths of light are emitted when an electron moves to a lower state as are absorbed when an electron moves to a higher state.
 
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