Is the Singularity of F(z) at z=0 Removable or a Pole?

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SUMMARY

The discussion centers on the nature of the singularity of the function F(z) at z=0, specifically whether it is removable or a pole. The sequence f_{n}=f(z/n) is analyzed to determine if it forms a normal family on the punctured disk. It is established that if the singularity is removable, then {f_n} converges uniformly to f(0), while if it is a pole, {f_n} diverges uniformly to infinity. Additionally, Picard's big theorem is referenced, indicating that an essential singularity leads to non-uniform convergence of {f_n}.

PREREQUISITES
  • Understanding of analytic functions and their properties
  • Familiarity with normal families in complex analysis
  • Knowledge of singularities, specifically removable singularities and poles
  • Comprehension of Picard's big theorem and its implications
NEXT STEPS
  • Study the properties of normal families in complex analysis
  • Learn about removable singularities and poles in analytic functions
  • Explore Picard's big theorem and its applications in complex analysis
  • Investigate uniform convergence and its significance in the context of sequences of functions
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Mathematicians, particularly those specializing in complex analysis, students preparing for preliminary exams, and anyone interested in the behavior of analytic functions near singularities.

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Hello All,
Just when I thought I understood whatever there was to understand about Normal Families...

F(z) is analytic on the punctured disk and we define the sequence
f_{n}=f(z/n) for n \leq 1.

Trying (and failing) to show that {f_n} is a normal family on the punctured disk iff the singularity of f(z) at z=0 is removable or a pole

Any help is appreciated, thank you
 
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Let D be a compact disk within the punctured disk. D doesn't contain the origin.
z/n -> 0 when n-> inf. So, the behaviour of {f_n} in D as in a neighbourhood of 0.
If the singularity is removable, {f_n} -> f(0) uniformly. If 0 is a pole,
{f_n} ->inf. uniformly ( because z^k .f_n(z) will be holomorphic for some k>=1).
Finally, Picard's big theorem guarantees that if 0 is an essential singularity,
f_n(z) assumes almost all values for sufficiently big n.Hence, the convergence can't be uniform.
 
I thank you very much Eynstone.
Need to study more...I am not prelim-ready yet
Regards
 
I thank you very much Eynstone.
Need to study more...I am not prelim-ready yet
Regards
 

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