Is the Triple Integral in Cylindrical Coordinates Correctly Solved?

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daphnelee-mh
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Homework Statement
(question is attached below)
Relevant Equations
x^2+y^2=r^2
dV=rdrdzdΘ
Typeset text: Evaluate the triple integral over V of (x^2 + y^2) dV, where V is the region enclosed by the paraboloid 2z = x^2 + y^2 and the planes z = 2, z = 8.


Handwritten derivation of a triple integral in cylindrical coordinates over region E, with sketches of the circles x^2+y^2=4 and 16 and of the paraboloid 2z=x^2+y^2 cut by planes z=2 and z=8.


I am trying to solve it using cylindrical coordinates, but I am not sure whether the my description of region E is correct, whether is the value of r is 2 to 4, or have to evaluate the volume 2 times ( r from 0 to 4 minus r from 0 to 2), and whether is okay to take z from r^2/2 to 8
 
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May I know which method did you use? I have no idea of it, thanks
 
Find attached my handwriting.
 
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  • Handwritten sketch of a paraboloid bowl opening upward with labelled circular cross-sections at z = 2, 2z and 8 and a z axis. Below is a top-down view of a shaded ring of radius rho and thickness d rho, labelled 2 pi rho d rho times z = rho^2 as the integrand.
    img20200703_17220936.png
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anuttarasammyak said:
[tex]\int_2^8 dz \int_0^{2z} 2\pi \rho^3 d\rho[/tex]
Shouldn't the boundary of integration be ##\sqrt{2z}## instead of ##2z##?
 
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Handwritten work: a sketch of a bowl-shaped paraboloid with the z-axis up, a horizontal line labelled y and a line labelled x, with height marks 2 and 4 and a level labelled sqrt(2z). Beside it, a triple integral of x^2+y^2 over the solid in cylindrical then spherical form, ending in the value 1008/3 pi.

Can you help to see whether this is correct ? Thank you
 
haruspex said:
The digits of 1008 add to 9, so...
?
 
haruspex said:
So 1008 is divisible by 3.
okay , thank you