MHB Is Theorem 5.2 in SET THEORY AND LOGIC True or False?

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Theorem 5.2 from "SET THEORY AND LOGIC" states that if for all sets A, A ∪ B = A, then B must be the empty set (0). The initial argument supports the theorem by showing that if A is the empty set, then B must also be empty. However, a counterexample is presented where A = {1, 2, 3} and B = {1, 2}, which satisfies A ∪ B = A while B is not empty. This indicates that the theorem is false, as the counterexample disproves the necessity of B being the empty set. Thus, the theorem does not hold true universally.
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In the book: SET THEORY AND LOGIC By ROBERT S.STOLL in page 19 the following theorem ,No 5.2 in the book ,is given:

If,for all A, AUB=A ,then B=0

IS that true or false

If false give a counter example

If true give a proof
 
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This is true.
To prove the same we have $A \cup B = A $ iff $B \subseteq A$

Let us take 2 sets $A_1,A_2$ which are disjoint and because it is true for every set $A_1 \cup B = A_1 $ so $B \subseteq A_1$

and $A_2 \cup B = A_2 $ so $B \subseteq A_2$

so from above 2 we have

$B \subseteq A_1 \cap A_2$

because $A_1,A_2$ are disjoint sets so we have $A_1 \cap A_2= \emptyset$

so $B = \emptyset$
 
[sp]Thanks ...Let $$\forall A[A\cup B=A]$$............1

put $$A=0$$ and 1 becomes $$0\cup B=0$$

And $$B=0$$ since $$0\cup B=B$$

Note 0 is the empty set

However somebody sujested the following counter example:

A={1,2,3}...B={1,2} so we have :$$A\cup B=A$$ and $$\neg(B=0)$$ [/sp]
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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