Is there a way to solve this convolution inequality?

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    Convolution Inequality
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SUMMARY

The discussion centers on the convolution inequality (g*v)(t) ≤ v(t) for functions g and v, where v is a positive function in L¹[0,T]. It is established that such a function g cannot exist under the given conditions. A counterexample is provided, demonstrating that if v is adjusted at t=0, the inequality fails, indicating the impossibility of satisfying the convolution inequality universally for all positive functions in L¹[0,T].

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amirmath
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Dear friends,

I am interesting to find some functions g satisfying the following convolution inequality

(g[itex]\ast[/itex]v)(t)[itex]\leq[/itex]v(t)

for any positive function v[itex]\in[/itex]L[itex]^{1}[/itex][0,T] and * denotes the convolution between g and v.
 
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amirmath said:
Dear friends,

I am interesting to find some functions g satisfying the following convolution inequality

(g[itex]\ast[/itex]v)(t)[itex]\leq[/itex]v(t)

for any positive function v[itex]\in[/itex]L[itex]^{1}[/itex][0,T] and * denotes the convolution between g and v.

The way you've worded the statement, it's not possible. Suppose that [itex]v \in L^1[0, T][/itex] satisfies 0 < (g*v)(0) < v(0). Let v'(t) = v(t) for all t other than 0 and v'(0) = .5(g*v)(0). Then v = v' in the sense of L1, but (g*v)(0) > v'(0).
 

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