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Homework Help: Is there anything wrong with this algebraically?

  1. Dec 12, 2011 #1
    1. The problem statement, all variables and given/known data

    http://img220.imageshack.us/img220/7554/daumequation13237539948.png [Broken]

    2. Relevant equations


    3. The attempt at a solution

    The denominator is two terms. If I take the reciprocal of both terms, does that change the value?
    Last edited by a moderator: May 5, 2017
  2. jcsd
  3. Dec 12, 2011 #2
    You would need to multiply by
    [tex]\frac{1}{1 + \frac{\sin^2 x}{\cos^2 x}} [/tex]
    Just remember that [itex]\displaystyle \frac{1}{A + B} \ne \frac{1}{A} + \frac{1}{B} [/itex]
  4. Dec 12, 2011 #3
    Ah, thanks for clearing that up.
  5. Dec 13, 2011 #4
    You could simplify it to

    [tex]\frac{\frac{Sin(x)}{Cos(x)}}{1+\frac{Sin^2(x)}{Cos^2(x)}} = Cos(x)Sin(x)[/tex]
    by multiplying by [tex]\frac{Cos^2(x)}{Cos^2(x)}[/tex]
    And then that could become [tex]Cos(x)Sin(x)=\frac{Sin(2x)}{2}[/tex]
    That's about as simple as you'll be able to get it though
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