# Is there anything wrong with this algebraically?

1. Dec 12, 2011

### tahayassen

1. The problem statement, all variables and given/known data

http://img220.imageshack.us/img220/7554/daumequation13237539948.png [Broken]

2. Relevant equations

N/A

3. The attempt at a solution

The denominator is two terms. If I take the reciprocal of both terms, does that change the value?

Last edited by a moderator: May 5, 2017
2. Dec 12, 2011

### JHamm

You would need to multiply by
$$\frac{1}{1 + \frac{\sin^2 x}{\cos^2 x}}$$
Just remember that $\displaystyle \frac{1}{A + B} \ne \frac{1}{A} + \frac{1}{B}$

3. Dec 12, 2011

### tahayassen

Ah, thanks for clearing that up.

4. Dec 13, 2011

### genericusrnme

You could simplify it to

$$\frac{\frac{Sin(x)}{Cos(x)}}{1+\frac{Sin^2(x)}{Cos^2(x)}} = Cos(x)Sin(x)$$
by multiplying by $$\frac{Cos^2(x)}{Cos^2(x)}$$
And then that could become $$Cos(x)Sin(x)=\frac{Sin(2x)}{2}$$
That's about as simple as you'll be able to get it though