Is there anything wrong with this algebraically?

[tahayassen]

Homework Statement

http://img220.imageshack.us/img220/7554/daumequation13237539948.png

Homework Equations

N/A

The Attempt at a Solution

The denominator is two terms. If I take the reciprocal of both terms, does that change the value?

 

[JHamm]

You would need to multiply by
$$\frac{1}{1 + \frac{\sin^2 x}{\cos^2 x}}$$
Just remember that $\displaystyle \frac{1}{A + B} \ne \frac{1}{A} + \frac{1}{B}$

 

[tahayassen]

Ah, thanks for clearing that up.

 

[genericusrnme]

You could simplify it to

$$\frac{\frac{Sin(x)}{Cos(x)}}{1+\frac{Sin^2(x)}{Cos^2(x)}} = Cos(x)Sin(x)$$
by multiplying by $$\frac{Cos^2(x)}{Cos^2(x)}$$
And then that could become $$Cos(x)Sin(x)=\frac{Sin(2x)}{2}$$
That's about as simple as you'll be able to get it though