# Is these algebraic expression correct

1.(x - 3)2 = 4
x2 - 6x + 5 = 0
(x - 1)(x - 5) = 0
x = -1, -5
(is this correct)

2. 2x + 4 / x +1 = x - 8 / 2x - 1
(2x + 4)(2x - 1) = (x - 8)(x + 1
4x2 - 2x + 8x - 4 = x2 - 7x -8
4x2 - 6x - 4 = x2 - 7x - 8
(where do i go from here)

3. (x / 3) - (y / 2) = -1
(y / 2) = -4 - 3x
6x + y = -8
y = -8 - 6x
(x / 3) - (-4 - 3x) = -1
(10 / 3) x + 4 = -1
x = -5 / (10 / 3) = (-3 / 2) x = -3 / 2
6(-3 / 2) + y = -8
y = -8 + 6(-3 / 2)
y = -8 + (-18 / 2)
y = (-144 +- 16 / 16) y = -10
(is this correct)

2. For this question, is what you're asking $$\frac{{2x + 4}}{{x + 1}} = \frac{{x - 8}}{{2x - 1}}$$? If so, it looks good. Now you simply want to subtract $$x^2 - 7x - 8$$ from both sides so you have 0 on the right side and a simple quadratic on the left.