1. The problem statement, all variables and given/known data A ball travelling in a straight line, colides with the end of a pole on a centre pivot, ie, the pole initially has inertia given by equation (ML^2)/12.After the colision, the ball sticks to the pole and the two rotate together. What is needed to be found is the angular speed use the variables m for mass of ball, d for length of pole, omega symbol for angular speed, v for speed of ball before colision. 2. Relevant equations cross product of vectors for ball initially are sued to generate the balls angular momentum. so, angluar momentum=(displacement vector) *(momentum vector) = L = r*p i take this as L=-d/2 *m*v this is also angular momentum intital, as the conservation of momentum is used to calulate the resulting angular speed. the final angular momentum = inertia *omega final inertia is equal to the sum of the two moment of inertias about the axis. this is mr^2 + (ML^2)/12 3. The attempt at a solution using -d/2 *m*v=(omega)(mr^2 + (ML^2)/12) rearange to isolate omega results in omega= [-d/2 *m*v]/[(mr^2) + (ML^2)/12] is this right though? im not sure ive done the cross product correctly.