Is this correct please - Binomial Theorem

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Homework Help Overview

The discussion revolves around the application of the Binomial Theorem to expand the expression (3n+1)^3. Participants are exploring the correctness of the expansion and the proper use of exponents in the binomial expansion.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to expand the expression using the Binomial Theorem but seems uncertain about the correct application of the theorem, particularly regarding the exponents and coefficients. Other participants question the accuracy of the expansion and point out potential errors in the original poster's approach.

Discussion Status

There is an ongoing examination of the original poster's expansion attempt, with some participants providing feedback on the errors identified. While corrections are suggested, there is no explicit consensus on the correct method yet, as the discussion is still unfolding.

Contextual Notes

Participants note that the original poster is a beginner, which may influence their understanding of the Binomial Theorem and its application. There is also mention of potential typos in the original expression.

Natasha1
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I'm a complete beginner at these:

(3n+1)^3 = (3n)^3 + 3(3n)^2 + 3(3n)^2 + 1

which would give me

= 3 (9n^3 + 6n^2) +1 is this correct?
 
Last edited:
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anyone :confused: ??
 
No, that is not correct.
(3n)^3 + 3(3n)^2 + 3(3n)^2 + 1
Your exponents should go from 3 down to 0.
3 (9n^3 + 6n^2) +1
This is also not correct.
 
Natasha1 said:
I'm a complete beginner at these:

(3n+1)^3 = (3n)^3 + 3(3n)^2 + 3(3n)^2 + 1
Perhaps it is a typo but you should not have "^2" twice.

which would give me

= 3 (9n^3 + 6n^2) +1 is this correct?
You have added 3(3n)^2 and 3(2n)^2 but the second shouldn't be squared.
 
thanks :-)
 

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