mathlearn
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$\sqrt{5} * \left(\frac{5}{4}\right)^{\!{\frac{1}{2}}}$
Many Thanks :)
Many Thanks :)
Hint: [math]x^{1/2} = \sqrt{x}[/math]mathlearn said:$\sqrt{5} * \left(\frac{5}{4}\right)^{\!{\frac{1}{2}}}$
Many Thanks :)
topsquark said:Hint: [math]x^{1/2} = \sqrt{x}[/math]
Can you finish from here?
-Dan
greg1313 said:$$\frac{5^{1/2}\cdot5^{1/2}}{2}$$
Does that help? (See topsquark's post).
mathlearn said:According to topsquark $\displaystyle x^{1/2} = \sqrt{x}$
$$\frac{\sqrt{5}\cdot\sqrt{5}}{2}=\frac{\sqrt{5}^2}{2}=\frac{5}{2}$$
Correct?
Many THanks :)