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Is this integration probelm right so far?

  1. Feb 25, 2008 #1
    [tex]\int_{e}^{infinity} \frac{dx}{x \ln x} = \int_{e}^{infinity} \frac{1}{x \ln x} dx = \int_{e}^{infinity} \frac{1}{\ln x} d \ln x = ln|lnx| + C [/tex]evaluated from e to infinity

    I think I know what I need to do next, I just want to make sure I'm good up to this point. Also, how do you put in an infinity sign, and evaluate sign? Thanks!
  2. jcsd
  3. Feb 25, 2008 #2
    Infinity is just \infty. Dunno about the other.

    Anyway, it looks correct to me.
  4. Feb 25, 2008 #3
    Looks right. (And divergent:smile:)
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