[tex]\int_{e}^{infinity} \frac{dx}{x \ln x} = \int_{e}^{infinity} \frac{1}{x \ln x} dx = \int_{e}^{infinity} \frac{1}{\ln x} d \ln x = ln|lnx| + C [/tex]evaluated from e to infinity(adsbygoogle = window.adsbygoogle || []).push({});

I think I know what I need to do next, I just want to make sure I'm good up to this point. Also, how do you put in an infinity sign, and evaluate sign? Thanks!

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# Is this integration probelm right so far?

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