Is This Solution Correct for f(x)=(x²)(ln x)(cos x)?

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Homework Help Overview

The discussion revolves around the function f(x) = (x²)(ln x)(cos x) and the intent to find its derivative. Participants are seeking clarification on the proper approach to differentiate this function.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are questioning the original poster's use of the term "solve" in relation to a function, suggesting a need for clearer problem definition. There is a discussion about applying the product rule for differentiation, particularly with multiple functions involved.

Discussion Status

The conversation is ongoing, with participants urging the original poster to clarify their question and provide details on their attempts. Some guidance on differentiation techniques has been offered, but no consensus or resolution has been reached.

Contextual Notes

There is a noted confusion regarding the terminology used by the original poster, as well as a suggestion that the problem may not align with typical homework phrasing. The context of the discussion implies a focus on derivative calculations.

teng125
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does anybody knows how to solve this:f(x)=(x^2) (ln x) (cos x) ??

i would like to know the final answer is it = exp (2/x + 1/x ln x - tan x)??
 
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We can't tell you the answer if you won't tell us the question! I don't know what you mean by "solve f(x)= ". Since you titled this "derivatives" I might guess you mean "find the derivative of f(x)" but in that case your "answer" makes no sense at all. I can only guess that you means something else entirely.

Please state the question clearly and don't just show an answer, show us how you got it.
 
ya,that's the question...myanswer it wrong.May i know how to do it??
 
I'll repeat:Please state the question clearly and don't just show an answer, show us how you got it.

I really doubt that you have a homework problem that says, word for word, "solve f(x)=(x^2) (ln x) (cos x)". It makes no sense to say "solve" a function.

Now, how did you attempt to do this problem?
 
Do you know that d(uv)/dx = v(du/dx) + u(dv/dx)
Now here you have three functions. Can you take two functions as one and then apply the above rule again i.e. apply it two times.
 
Have they move teaching about derivatives, to precalculus courses? :confused:
 

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