Is This the Correct Method to Solve the Conservation of Energy Problem?

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Homework Help Overview

The problem involves applying the Principle of Conservation of Energy to determine the distance a block slides down an inclined plane before compressing a spring. The scenario includes a block of mass 5kg, an incline of 30 degrees, and a spring with a specified spring constant.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to use the conservation of energy equation to relate gravitational potential energy to spring potential energy. They express uncertainty about their trigonometric application in determining the distance D.

Discussion Status

Participants are actively engaging with the original poster's approach, providing feedback on the trigonometric relationships involved. Some guidance has been offered regarding the correct application of sine and cosine in the context of the problem.

Contextual Notes

There appears to be a focus on the correct interpretation of the geometry related to the inclined plane and the relationships between the height and distance. The original poster's calculations are questioned, particularly regarding the trigonometric functions used.

teme92
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Homework Statement



Using the Principle of Conservation of Energy, solve:

A block of mass 5kg is released from rest and slides down a distance D
down a smooth plane inclined at 30◦ to the horizontal. It then strikes a
spring compressing it 10cm before it begins to move up the plane. If the
spring constant is 980N/m and g = 9.8m/s2, find D.

Homework Equations



mgh=0.5(k)(x^2)

d=hcos(theta)

The Attempt at a Solution



Using mgh=0.5(k)(x^2)

5(9.8)h=0.5(980)(.01)^2

and got h on its own for:

h=0.001

Then I used d=hcos(theta) to get:

d= (.001)cos(30)

d= 8.66×10^-4

Is this the correct way of doing the question? Thanks for any advice.
 
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Your trig is wrong. D is the hypotenuse of the triangle, and h is the side opposite the angle. Draw a picture.
 
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Hi cepheid thanks for the quick reply.

I see so d=h/sin30 then is it?
 
teme92 said:
Hi cepheid thanks for the quick reply.

I see so d=h/sin30 then is it?

That is correct. The rest of your work (applying the conservation of energy( looks fine.
 
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Brilliant! Thanks a million for the help!
 

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