Is Two-Colour Bead Necklace Arrangement Possible?

  • Context: MHB 
  • Thread starter Thread starter evinda
  • Start date Start date
  • Tags Tags
    Bead
Click For Summary

Discussion Overview

The discussion revolves around the possibility of arranging a necklace with 64 beads of 8 different colors such that all possible pairs of colors appear exactly once when traversing the necklace in either direction. This involves concepts from combinatorial design and De Bruijn sequences.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • Some participants propose that the arrangement can be modeled as a De Bruijn sequence, specifically $B(8,2)$, which would allow for all pairs of colors to be seen exactly once.
  • Others question how to prove the existence of such a sequence, suggesting that existing constructions and proofs, such as those found in graph theory literature, may provide insights.
  • A participant references a specific example of a De Bruijn sequence and provides a link for further exploration.

Areas of Agreement / Disagreement

Participants generally agree on the relevance of De Bruijn sequences to the problem, but the discussion includes questions about the proof of existence and construction methods, indicating that multiple views and uncertainties remain.

Contextual Notes

The discussion does not resolve the mathematical steps necessary to prove the existence of the De Bruijn sequence for this specific case, nor does it clarify the assumptions about the arrangement of the beads.

evinda
Gold Member
MHB
Messages
3,741
Reaction score
0
Hello! (Wave)

We have a necklace with $64$ beads from $8$ different colours. Is it possible that they are put in such a way that if we go along the necklace in one direction (in any of the two) then we see all the possible successions of two colours exactly once?
 
Physics news on Phys.org
evinda said:
Hello! (Wave)

We have a necklace with $64$ beads from $8$ different colours. Is it possible that they are put in such a way that if we go along the necklace in one direction (in any of the two) then we see all the possible successions of two colours exactly once?
This is called a De Bruijn sequence. (I'm assuming that the necklace is joined up at the ends so as to form a cyclic sequence of beads.)

The sequence that you want is the De Bruijn sequence $B(8,2)$. If you want to see an example, here it is (with the colours labelled $0$ to $7$).

[sp]http://www.hakank.org/comb/debruijn.cgi?k=8&n=2&submit=Ok[/sp]
 
Opalg said:
This is called a De Bruijn sequence. (I'm assuming that the necklace is joined up at the ends so as to form a cyclic sequence of beads.)

The sequence that you want is the De Bruijn sequence $B(8,2)$. If you want to see an example, here it is (with the colours labelled $0$ to $7$).

[sp]http://www.hakank.org/comb/debruijn.cgi?k=8&n=2&submit=Ok[/sp]

And how could we prove that such a sequence exists? (Thinking)
 
evinda said:
And how could we prove that such a sequence exists? (Thinking)
The construction of $B(2, 4)$ is illustrated in the wiki article. That should explain how to construct such sequences. You can see the proof of the general statement in West's Introduction to Graph Theory. Look for "De-Bruijn Cycles" in the index.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
6
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 40 ·
2
Replies
40
Views
4K