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A while ago, robphy posted a link to a paper by Saulson describing a "step" gravitational wave described by the metric ##ds^2=-dt^2+[1+h(t)]dx^2+[1-h(t)]dy^2##, where ##h(t)=h_0H(t-\tau)## is a step function of (constant) height ##h_0##, with the step occurring at ##t=\tau##. Presumably, ##\tau## is a function of time and the suppressed ##z## dimension.
I was wondering about Feynman's sticky beads in such a metric. As I understand it, if I aligned the rod parallel to the x direction then the distance between two beads jumps from ##l## to ##l\sqrt { 1+h_0}## as the gravitational wave comes through (more precisely, the round trip time for light pulses traveling from one bead to the other and back goes up by a factor of ##\sqrt{1+h_0}##, which I choose to interpret as a distance change). Similarly, the rod's length increases by the same factor - but it has structural strength, so it immediately begins to relax. Thus, the way I'm describing things, in this case the heating effect comes from the contracting rod moving through the (initially stationary) beads.
Normally Feynman's beads are described in terms of the beads moving on a rigid rod. Am I right in thinking that there's no sensible way of using this description in this scenario because there's no way to define a rigid unstressed rod when the gravitational wave is passing through? However, more realistic waves (like those detected by LIGO) are periodic (ish) on a timescale of order 0.1s. Since we would expect stresses in a metal rod (length 1m, speed of sound ~1km/s) to relax away in a few milliseconds, it can be treated as rigid. The length changes as a result of the metric are relaxed away as fast as they accumulate. In that case it makes sense to think of the beads moving along the rod because the changes in the rod length get relaxed away while the changes in the bead separation continue to accumulate.
Is that all correct?
I was wondering about Feynman's sticky beads in such a metric. As I understand it, if I aligned the rod parallel to the x direction then the distance between two beads jumps from ##l## to ##l\sqrt { 1+h_0}## as the gravitational wave comes through (more precisely, the round trip time for light pulses traveling from one bead to the other and back goes up by a factor of ##\sqrt{1+h_0}##, which I choose to interpret as a distance change). Similarly, the rod's length increases by the same factor - but it has structural strength, so it immediately begins to relax. Thus, the way I'm describing things, in this case the heating effect comes from the contracting rod moving through the (initially stationary) beads.
Normally Feynman's beads are described in terms of the beads moving on a rigid rod. Am I right in thinking that there's no sensible way of using this description in this scenario because there's no way to define a rigid unstressed rod when the gravitational wave is passing through? However, more realistic waves (like those detected by LIGO) are periodic (ish) on a timescale of order 0.1s. Since we would expect stresses in a metal rod (length 1m, speed of sound ~1km/s) to relax away in a few milliseconds, it can be treated as rigid. The length changes as a result of the metric are relaxed away as fast as they accumulate. In that case it makes sense to think of the beads moving along the rod because the changes in the rod length get relaxed away while the changes in the bead separation continue to accumulate.
Is that all correct?