Is {v1,...,vk} Linearly Independent Given vi.vj=0 When i≠j?

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suppose v1,...,vk are nonzero vectors with the property that vi.vj=0 whenever i is not equal to j. Prove that {v1,...,vk} is linearly independent.
 
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Suppose \alpha_1, \ldots, \alpha_k are such that 0 = \alpha_1 v_1 + \ldots + \alpha_k v_k. Try taking the dot product of this equation with each of the v_is and see what it tells you about the \alpha_is.
 
thank u, i got it now...
 

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