Is (x-h)^4(y-k)=Some Constant Also an Equation of a Rectangular Hyperbola?

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Discussion Overview

The discussion revolves around whether the equation (x-h)^4(y-k)=some constant can be classified as an equation of a rectangular hyperbola. Participants explore the implications of the fourth power on the shape and characteristics of the curve compared to traditional rectangular hyperbolas.

Discussion Character

  • Debate/contested

Main Points Raised

  • One participant states that the general equation for a rectangular hyperbola is (x-h)(y-k)=some constant and questions if (x-h)^4(y-k)=some constant can also represent a rectangular hyperbola.
  • Another participant specifies the standard form of a rectangular hyperbola as xy=a^2 and discusses how the equation (x-h)^4(y-k)=a^2 would affect the graph, noting a shift in the center to (h,k) and the graph lying in the first and third quadrants.
  • A third participant argues that with the fourth power, the equation will not represent a hyperbola at all, asserting that hyperbolas are defined as conic sections with second-degree equations.
  • A follow-up question is raised regarding how to graph such a function or determine its points of intersection with the axes.

Areas of Agreement / Disagreement

Participants express disagreement regarding the classification of the equation as a hyperbola, with some asserting it cannot be a hyperbola due to its degree, while others explore its graphical characteristics without reaching a consensus.

Contextual Notes

The discussion includes assumptions about the definitions of hyperbolas and the implications of altering the degree of the equation, which remain unresolved.

gliteringstar
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the general equation for rectangular hyperbola with vertical and horizontal asymptotes is given as :

(x-h)(y-k)= some constant

Is the following also an equation of rectangular hyperbola

(x-h)^4(y-k)=some constant ?

I am trying to find the shape of this curve,is it similar to that of rectangular hyperbola?
 
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...to be more precise...

the cartesian equation of rectangular hyperbola in question is given by:

xy=a^2

If we have it as (x-h)^4(y-k)=a^2,will the shape of graph of this rectangular hyperbola change?...the centre is different of course...it has shifted to (h,k) with the two parts of the graph lying in the newly formed first and third quadrant...

someone please reply!
 
With the fourth power, it will NOT be a hyperbola at all- though it may look somewhat like one. A "hyperbola", is defined as being one of the "conic sections" and so its equation must be second degree, not fifth degree as you give.
 
thank you :)

But how do we find the graph of such a function?and if not the graph,can we get some idea about point of intersection of graph of this function with any of the axes?
 

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