Isomorphisms between cyclic groups? (stupid question)

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SUMMARY

Z mod 2 x Z mod 3 is isomorphic to Z mod 6 due to the coprimality of 2 and 3, while Z mod 2 x Z mod 2 is not isomorphic to Z mod 4 because 2 is not coprime to itself. This relationship is explained by the structure theorem for abelian groups, which states that the direct product of two cyclic groups is cyclic if and only if their orders are coprime. The discussion emphasizes that for a direct product G x H to be cyclic, the orders of G and H must be coprime.

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Why is Z mod 2 x Z mod 3 isomorphic to Z mod 6 but Z mod 2 x Z mod 2 not isomorphic to Z mod 4?
 
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On what level do you want the 'why' explained? I suppose the 'real' answer is because 2 and 3 are coprime, but 2 is not coprime to 2.

This is either a consequence of the structure theorem for abelian groups, or an explanation of that theorem, depending on how you look at it.

We could look a bit deeper: suppose that G and H are cyclic, when is GxH cyclic? Well, suppose that we claim (g,h) is a cyclic generator of GxH. Well, g must be a generator of G with order p, say, and h a generator of H with order q, and (g,h) must have order pq. If I raise (g,h) to the power p, then it is (1,k) for some k in H, and in order for (g,h) to have order pq k must have order q, i.e. also be a generator for H.

Pulling out the important thing: H must have an element h of order so that h^p still has order q. But this is if and only if p is coprime to q (this is an elementary fact you may have learned already).
 

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