Isothermal process, Calculate the density

[dbag123]

Homework Statement

1000L of air at 2Bar, how does the density change when the volume is reduced to 200L, initial temperature is 288K assuming it is a isothermal process.

Relevant Equations

p1v1=p2v2

I can get the P2 from P1V1=P2V2 --> P2 = 10Bar,

but then how do i get the density?
p=p/R*T ? where p=10Bar R=287J K^-1kg and T 288K, density would be 12,1kg/m³?
Is that right?

 

[rude man]

It asks how the density changes. I interpret that as a ratio or percentage question.

The answer should then be obvious.

 

[dbag123]

assuming the desntity to be 1,209kg/m³ at 1 atm, then 10 atm would be 10x ?

 

[dbag123]

assuming the desntity to be 1,209kg/m³ at 1 atm, then 10 atm would be 10x ? and as such the change in density 5x to the original

 

[rude man]

yes, 1000mL/200 mL = 5.
No physics needed!