Isothermal process, Calculate the density

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Homework Help Overview

The discussion revolves around an isothermal process and the calculation of density under varying pressure conditions. Participants are exploring how density relates to pressure changes in a gas, specifically using the ideal gas law and assumptions about initial conditions.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to derive density from pressure and temperature values, questioning the validity of their calculations. There is also a discussion on how density changes with pressure, including interpretations of the problem as a ratio or percentage change.

Discussion Status

The discussion is active, with participants providing various interpretations of how density should be calculated and how it changes with pressure. Some guidance has been offered regarding the relationship between pressure and density, but there is no explicit consensus on the correct approach or final answer.

Contextual Notes

Participants are working under the assumption of ideal gas behavior and are referencing specific initial conditions, such as density at 1 atm. There is some ambiguity regarding the interpretation of how density changes, with different participants suggesting varying methods of calculation.

dbag123
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Homework Statement
1000L of air at 2Bar, how does the density change when the volume is reduced to 200L, initial temperature is 288K assuming it is a isothermal process.
Relevant Equations
p1v1=p2v2
I can get the P2 from P1V1=P2V2 --> P2 = 10Bar,

but then how do i get the density?
p=p/R*T ? where p=10Bar R=287J K-1kg and T 288K, density would be 12,1kg/m3?
Is that right?
 
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It asks how the density changes. I interpret that as a ratio or percentage question.

The answer should then be obvious.
 
assuming the desntity to be 1,209kg/m3 at 1 atm, then 10 atm would be 10x ?
 
dbag123 said:
assuming the desntity to be 1,209kg/m3 at 1 atm, then 10 atm would be 10x ? and as such the change in density 5x to the original
 
yes, 1000mL/200 mL = 5.
No physics needed!
 

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