1) Isotropic loudspeaker A certain loudspeaker system emits sound isotropically(adsbygoogle = window.adsbygoogle || []).push({});

with a frequency of 2.00 x 103 Hz and an intensity of 1.00 x 10-3 W/m2 at a distance of 7.00 m.

Assume there are no reflections. Use 344 m/s for the velocity of sound in air and 1.21 kg/m3 for

the density of air.

a) What is the displacement amplitude at 7.00 m?

b) What is the pressure amplitude at 7.00 m?

c) What is the intensity at 25.0 m?

Hi, does the term isotropic change the way I calculate the displacement amplitude or does the wave still propagate in the +x direction?

I want to use these formulas,

v = sqrt(B/p) B is the bulk modulus and p is the density.

v = (f)(wavelength)

I = 1/2(sqrt(pB)(w^2)(A^2) = (p_max^2)/(2pv)

= (p_max^2)/(2(sqrt(pB))

for the intensity formula denoted I. p = density and p_max is the pressure amplitude which is directly proporional to A, the displacement amplitude.

please let me know if I can use these formulas for this case.. thank you!!

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# Homework Help: Isotropic loudspeaker - calc based

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