J.J Thomson's determination of of the ratio m/e

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SUMMARY

J.J. Thomson's experimental determination of the mass-to-charge ratio (m/e) of an electron utilized electric and magnetic fields, represented by intensities E and H respectively. The governing equations of motion were derived as m(d²x/dt²) + He(dy/dt) = 0 and m(d²y/dt²) - He(dx/dt) = 0. The resulting path of the electron is a cycloid, with parametric equations defined as x = {Em/H²e}(1 - cos([He/m]t)) and y = {Em/H²e}([He/m]t - sin([He/m]t)). The discussion also emphasizes the calculation of net forces ΣFx and ΣFy in terms of E, H, and e.

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nddewaters
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In Thomson's experimental determination of the ratio m/e of the mass to the charge of an electron, in which the electrons were subjected to an electric field of intensity E and a magnetic field of intensity H, the equations

m[d2x/dt2) + He(dy/dt) , m[d2y/dt2) - He(dx/dt) = 0 ,

were employed. If x=y=dx/dt=dy/dt=0 for t=0, show that the path is a cycloid whose parametric equations are:

x = {Em/H2e}(1 - cos([He/m]t))
y = {Em/H2e}([He/m]t - sin([He/m]t))

Good Luck.
 
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find [tex]\Sigma[/tex]Fx [tex]\Sigma[/tex]Fy in terms of E,H,e etc.
[tex]\Sigma[/tex]Fx = md2x/dt2
[tex]\Sigma[/tex]Fy = md2y/dt2
and solve the differential equations.
 

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