Just a few questions relating to graphs

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SUMMARY

The discussion focuses on the interpretation of current-voltage graphs in the context of electrical power calculations. The slope of the current-voltage graph is confirmed to be 1/R, where R represents resistance. The participant questions the validity of calculating power as the area under the line, specifically contrasting the calculation of power using the formula P = IV with the area of a triangle, leading to confusion regarding the correct interpretation of power in this context.

PREREQUISITES
  • Understanding of Ohm's Law and its application in electrical circuits.
  • Familiarity with the concept of power in electrical systems.
  • Knowledge of graph interpretation, specifically current-voltage relationships.
  • Basic understanding of geometric area calculations (rectangles and triangles).
NEXT STEPS
  • Study the relationship between current, voltage, and resistance using Ohm's Law.
  • Learn about power calculations in electrical circuits, focusing on P = IV.
  • Explore the significance of the area under the curve in various types of graphs.
  • Investigate the differences between calculating areas of rectangles and triangles in graph analysis.
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Students studying electrical engineering, physics students preparing for exams, and educators seeking clarification on power calculations in current-voltage graphs.

ianb
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I'm not following the format because this isn't really a homework question -- I'm just studying for my finals and encountered a few graphs in the electricity unit, and want a few things cleared up.

So in a current-voltage graph, the slope is 1/R, and power (according to my teacher) is the area under the line. I only have a problem with the latter claim-- say we have a point on a linear line whose coordinate is (20,4). Should P = IV = 20 x 4 = 80 rather than P = Area = 20 x 4 x 0.5 = 40?
 
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Yes, power should be area of the rectangle rather than area of the triangle.
 

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