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Homework Help: Just a few questions relating to graphs

  1. May 15, 2007 #1
    I'm not following the format because this isn't really a homework question -- I'm just studying for my finals and encountered a few graphs in the electricity unit, and want a few things cleared up.

    So in a current-voltage graph, the slope is 1/R, and power (according to my teacher) is the area under the line. I only have a problem with the latter claim-- say we have a point on a linear line whose coordinate is (20,4). Should P = IV = 20 x 4 = 80 rather than P = Area = 20 x 4 x 0.5 = 40?
  2. jcsd
  3. May 15, 2007 #2


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    Yes, power should be area of the rectangle rather than area of the triangle.
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