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Finding Distance from the Origin Given Velocity Graph

  1. Sep 18, 2016 #1
    1. The problem statement, all variables and given/known data
    A rocket-powered hockey puck move along a horizontal friction-less table. The figure (link posted below) shows the graphs of vx and vy, the x- and y- components of the puck's velocity. The puck starts at the origin. How far from the origin is the puck at 4 seconds?

    Here is the picture of the two graphs: https://session.masteringphysics.com/problemAsset/1384028/7/4-9.jpg

    [moderator's edit: Here's an inserted copy of the image just in case the link evaporates some day]
    upload_2016-9-18_14-15-13.png
    2. Relevant equations
    area of a triangle: 1/2(b)(h)
    area of a square: (l)(w)
    sqrt(x2+y2)

    3. The attempt at a solution
    It appears on the on the vx graph that the velocity increases by an increment of 8 cm every second. (It is confirmed to be at 40 cm at 5 seconds). So I thought the way to do this would be to find the area under both graphs from 0 to 4 seconds.
    On the vx graph, I found the area to be 1/2*4*32 = 64 cm. On the vy graph, I found the area to be 30*4 = 120 cm. Then I tried to use the formula for distance to solve and came out with:
    sqrt(642 + 1202) = 136 cm.

    However, whenever I put this answer in, it says it is incorrect. I guess I'm not really the best at physics, so I'm wondering where it was I made the error? I appreciate any help.
     
  2. jcsd
  3. Sep 18, 2016 #2
    Strange as your answer seems to be correct at least from my judgement
    I suppose make sure your answer is rounded correctly and that if required your answer is inputted with the correct units
    Other than that I do not see an issue with your method
    Maybe significant figures or something?
     
  4. Sep 18, 2016 #3
    Oh I see now that the site wants the answer to two significant figures. So that would be 1.4 meters then?
     
  5. Sep 18, 2016 #4
    I believe so
     
  6. Sep 18, 2016 #5
    It worked that time. Thank you!
     
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