KE in terms of P Pretty sure Ive got most of it

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In summary, an explosion causes an object to break into two pieces, one of which has 1.60 times the mass of the other. If 7100 J of energy is released in the explosion, the larger piece acquires 2730 J of kinetic energy, while the smaller piece acquires 4369 J of kinetic energy. This is based on the conservation of momentum and energy principles.
  • #1
MJC8719
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An explosion breaks an object into two pieces, one of which has 1.60 times the mass of the other. If 7100 J were released in the explosion, how much kinetic energy did each piece acquire?

Heavier Piece

Lighter Piece

Express KE in terms of P

I think I have done most of the work here...its the last part of the problem that's tripping me up

Heres my work:

The explosion causes the piece (which I'm assuming explodes while at rest) to break into two pieces. Conservation of momentum states that they must go in opposite directions (you can verify this on your own). So, we have our first equation:

mv1 + 1.6mv2 = 0
mv1 = -1.6mv2
v2 = -v1/1.6

I use v1 for the velocity of the lighter piece, and v2 for the heavier piece. The energy of the explosion is transferred to the pieces and causes it to move, so the sum of the kinetic energies of the two pieces combined must equal 7100 J. Our second equation is:

1/2mv12 + 1/2 (1.6m)v22 = 7100

If we substitute v2 with what we got before with momentum conservation, then we can get the left hand side to be in terms of m and v1 only. We can't find the values of m and v1 directly, but we know that the kinetic energy (of the lighter piece) is 1/2mv12, which we can find after rearranging the equation so that it is in the form of kinetic energy:

1/2mv12 + 1/2(1.6m)(-v1/1.6)2 = 7100 J
1/2m(v12+v12/1.6) = 7100 J
1/2m(1.625v12) = 7100 J
1/2mv12 = 4370 J

Now here's where it starts to get a little tricky:

The final line reads: 1/2 mv1^2 = 4370.

So, we also then know that K = 1/2mv^2 = (1/2)(m^2v^2/m) = p^2/2m

Therefore, p^2/2m = 4370
So, the energy for lighter piece would then equal 4370 - p^2/2m and thus the energy for the heavier piece would just be 1- that.

Is this correct? I am slighty confused by the fact that my answer has to be in terms of P.

Thanks for the help
 
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  • #2
Try this. You know how v_1 and v_2 compare to each other. Use that to compare KE_1 to KE_2. Then use the total KE to find KE_1 and KE_2 explicitly.
 
  • #3
Ok,

So if i understand you correctly you are saying that we know v2 = -v1/1.6.

We also know that KE1 + KE2 = 7100J

So, KE1 = 1/2mv1^2 and therefore KE2 = 1/2(1.6m)v2^2 but we know that v2 = -v1/1.6 so therefore we can say that

KE2 = (1/2)(1.6m)(-v1/1.6^2)

So we can then have the equation
1/2mv1^2 + (1/2)(1.6m)(-v1/1.6^2) = 7100

Is this correct so far??

If we continue this we would get
1/2 mv1^2 + (0.8m)(v1^2/2.56) = 7100

1/2 mv1^2 + .31250 v1^2 = 7100

p^2/2m + .31250v1^2 = 7100

And this is where i get stuck if i have done the above correctly... your help is really appreciated
 
  • #4
MJC8719 said:
Ok,

So if i understand you correctly you are saying that we know v2 = -v1/1.6.

We also know that KE1 + KE2 = 7100J

So, KE1 = 1/2mv1^2 and therefore KE2 = 1/2(1.6m)v2^2 but we know that v2 = -v1/1.6 so therefore we can say that

KE2 = (1/2)(1.6m)(-v1/1.6^2)
So what is KE2 in terms of KE1?

(Forget about expressing KE in terms of P; that's not helpful here.)
 
  • #5
Hmm,

So if I understand this then if we simplify
KE2 we find that it equals 0.31250mv1^2.
KE1 then equals 0.5mv1^2.

So if we make KE1 ="1" or KE1 - mv1^2 then KE2 = .0625mv1^2 of KE1.

Is this what you mean. If so, then could you give me a hint as to what the next step is?
 
  • #6
MJC8719 said:
Hmm,

So if I understand this then if we simplify
KE2 we find that it equals 0.31250mv1^2.
KE1 then equals 0.5mv1^2.
Now express KE2 in terms of KE1. (Just like you wrote v2 in terms of v1: v2 = v1/1.6.)
 
  • #7
Suddenly, it clicked Doc...Thanks for the help. I was getting hung up on the whole solve for p part

I think the "write K in terms of p" is just a hint:

total momentum before = total momentum after so

0 = M v - m V where M = 1.60 m so V = 1.60 v

Now total energy:

E total = (1/2) M v2 + (1/2) m V2 or

E total = (1/2) M v2 + (1/2) (M/1.60) ( 1.60 v)2


E total = (1/2) M v2 + 1.60 (1/2) M v2 or

E total = ( 1 + 1.60 ) (1/2) M v2 notice that the last bit is just the KE of the larger piece so

E total = 2.60 K of larger piece so

71000 / 2.60 = K or larger piece or

K of larger piece = 27308 J and the smaller piece gets the rest,

71000 - 27308 = 43692 J

Now i Understand it...though i realizied i added an extra zero and made it 71000 instead of 7100.

Thanks for the help
 

1. What is the relationship between kinetic energy and potential energy?

Kinetic energy (KE) and potential energy (PE) are both forms of energy that an object possesses. Kinetic energy is the energy an object has due to its motion, while potential energy is the energy an object has due to its position or shape. The two are related in that potential energy can be converted into kinetic energy and vice versa, as described by the Law of Conservation of Energy.

2. How is kinetic energy calculated?

Kinetic energy is calculated using the equation KE = 1/2 * m * v^2, where m is the mass of the object in kilograms and v is the velocity of the object in meters per second. This equation shows that the greater the mass and velocity of an object, the greater its kinetic energy will be.

3. What are some examples of kinetic energy?

Some examples of kinetic energy include a moving car, a swinging pendulum, a bouncing ball, and a running person. Essentially, any object that is in motion possesses kinetic energy.

4. How does potential energy change with an object's position?

Potential energy changes with an object's position because it is dependent on the height of the object and the strength of the gravitational field it is in. The higher an object is, the greater its potential energy will be. As the object falls and its position changes, its potential energy will decrease and its kinetic energy will increase.

5. How do the units for kinetic and potential energy differ?

The units for kinetic energy are typically joules (J), while the units for potential energy can vary depending on the type of potential energy being measured. For example, gravitational potential energy is measured in joules, while electrical potential energy is measured in volts (V). However, both forms of energy can be measured in the same unit of joules if necessary.

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