Keplerian beam expander output diameter?

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The discussion focuses on a homework problem involving a beam expander made of two converging lenses with differing focal lengths. The task is to demonstrate that the outgoing beam diameter is proportional to the ratio of the focal lengths, specifically (f1/f2)*d, where d is the initial beam diameter. Participants discuss the correct ray diagram and the use of similar triangles to prove the relationship. The conversation highlights the importance of understanding the behavior of rays passing through the focal points of the lenses. The discussion emphasizes the need for clarity in applying geometric principles to solve the problem.
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Homework Statement



Draw the path of two parallel incident rays in a beam expander composed of two convering thin lens, with the first lens having a focal length less than the second one (f1 < f2.)

Kind of what the problem looked like.

TT48_Fig3.25.jpg


The distances between the two parallel rays (the beam diameter) was given as d. Prove that the outgoing beam diameter is (f1/f2)*d (given.)

Homework Equations


1/s+1/s'=1/f
m=-s'/s

The Attempt at a Solution



I had the ray diagram correct but I have no idea how to begin proving it. :confused:
 
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Anyone?
 
Use similarity.

ehild
 
I thought about it and I still don't know how to do it.
 
You know that those rays which travel through the focus will be parallel with the axis after traversing the lens.

See the blue and red isosceles triangles in the picture. They are similar.

ehild
 

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