Given that Jupiter has a mass of 1.9x10^27 kg, and the sun has a mass of 1.99x10^30 kg:
a) Calculate the value of Kepler's constant for Jupiter.
b) If Jupiter's orbital period is 11.89 Earth years, calculate the average radius of its orbit.
K = Gmp/4pi^2 = r^3/T^2
11.89x365x24x3600 = 374963040
The Attempt at a Solution
For a) Kjupiter = Gmp/4pi^2
= 3.21x10^15 m^3/s^2
b) Ksun = Gmp/4pi^2
ksun = (6.67x10^-11)(1.99x10^30)/4pi^2
Therefore: r^3 = Ksun*T^2
r = cubed rt. of Ksun*T^2
r = cubed rt. of (3.36x10^18)(374963040)^2
r = cubed rt. of 4.724068653x10^35
r = 7.8x10^11m
I am really unconfident about these answers, can someone tell me if I am one the right track or should give up on Physics?
Thank you in advance.