A satellite orbits a planet at a distance of 6.80 multiplied by 10^8 m. Assume that this distance is between the centers of the planet and the satellite and that the mass of the planet is 3.08 multiplied by 10^24 kg. Find the period for the moon's motion around the earth. Express the answers in earth days
Kepler's 3rd Law
Period² = (4(pi)radius³)/(Gravitational Constant * Mass of Massive Body)
The Attempt at a Solution
I have the answer in days of this planet, however, I don't know how to get the answer in Earth days.
7779136.049 = Period.
I'm incredibly sure this is a correct value, I've done multiple calculations and always got within 0.1% of this value
I saw this question in the archive, but I don't believe anyone realized the answer was in Earth days or they just did not show their work (which is what I was hoping to see).
Found my problem, needed to divide by days represented in seconds (Period / (60 * 60 * 24));
Answer was 90 days. (decimal dropped out of laziness, forgive me significant digits.)