A orbiting satellite stays over a certain spot on the equator of (rotating) Mercury. What is the altitude of the orbit (called a "synchronous orbit")?
Mercury mass = 3.3022 e23 kg
Mercury Radius = 2439.7 km
[tex]T^2[/tex] = (4[tex]\Pi^2[/tex]/GM) * r^3
and that's all I can think of which is why I'm stuck
The Attempt at a Solution
I'm sorry that I have no attempt, I'm really lost on this one and would greatly appreciate any help!