Kernels, and Representations of Diff. Forms.

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SUMMARY

The discussion focuses on the definition of the hyperplane field \( T_x\Sigma < T_pM \) on the manifold \( M = \Sigma \times S^1 \), where \( \Sigma \) is a surface. It establishes that this hyperplane field is defined as the kernel of the differential form \( d\theta \), which is the top form on \( S^1 \). The conversation also addresses the relationship between tangent spaces and the dual cotangent bundle \( T^*pM \), emphasizing the need for a linear map on the sum of vectors from the tangent spaces of \( M \) and \( N \) at points \( x \) and \( y \). The pullback of \( d\theta \) via the natural projection from \( M \times S \) to \( S \) is also discussed, confirming that the kernel is indeed \( TM \).

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WWGD
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Hi, All:

I need some help with some "technology" on differential forms, please:

1)Im trying to understand how the hyperplane field Tx\Sigma<
TpM on M=\Sigma x S1 , where \Sigma
is a surface, is defined as the kernel of the form dθ (the top form on S1).

I know that T(x,y)(MxN)≈TxM(+)TyM

But this seems to bring up issues of the dual Tp*M,

i.e., the cotangent bundle of M .

How do we define a linear map on a sum vm+vn , each

a vector on the tangent spaces of M,N at x,y respectively? I think this may have

to see with the tensor product, but I'm not sure.

Thanks .
 
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dθ is defined on the product as the pullback by the natural projection M x S -- > S. It's value on v + w is then dθ(w) (for v in TM, w in TS). So it's kernel is TM.

Does this answer your question?
 

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