Killing vectors for Anti desitter space in 3+1

  • Context: Graduate 
  • Thread starter Thread starter Jim Kata
  • Start date Start date
  • Tags Tags
    Space Vectors
Click For Summary
SUMMARY

The discussion focuses on deriving the Lie algebra for Anti-de Sitter (AdS) space in 3+1 dimensions, specifically using the O(4,1) symmetry group. The user attempts to derive conformal Killing vectors by solving Killing's equation but encounters issues with the conformal factor vanishing. The provided Killing vectors satisfy the equation but only yield four unknowns (A, B, C, D) instead of the expected ten from SO(1,4). The user seeks clarification on how Teitelboim and Henneaux derived their Lie algebra in their paper on asymptotically AdS spaces.

PREREQUISITES
  • Understanding of Anti-de Sitter space geometry
  • Familiarity with Killing's equation and conformal Killing vectors
  • Knowledge of Lie algebras and their representations
  • Basic concepts of O(n,m) symmetry groups
NEXT STEPS
  • Study the derivation of conformal Killing vectors in detail
  • Examine the paper by Teitelboim and Henneaux on asymptotically AdS spaces
  • Learn about the embedding of AdS in Minkowski space
  • Research the properties of the O(n,m+1) group and its relation to isometries of AdS
USEFUL FOR

The discussion is beneficial for theoretical physicists, mathematicians studying differential geometry, and researchers working on gravitational theories involving Anti-de Sitter space.

Jim Kata
Messages
197
Reaction score
10
I'm trying to derive the lie algebra for Anti desitter space in 3+1 I know it's O(4,1) and I think I understand that but I'm taking different approach. I tried to derive the conformal killing vectors by solving Killing's equation, but when I got my solution the conformal factor vanished :confused: .

The solution I got for the Killing vectors is:




<br /> \xi _t = - r\sqrt {1 + \left( {r/R} \right)^2 } \sin \theta \left( {A\sin \phi \cos \left( {t/R} \right) - B\cos \phi \cos (t/R) + C\sin \phi \sin (t/R)} \right)<br />

<br /> \xi _r = \frac{R}<br /> {{\sqrt {1 + \left( {r/R} \right)^2 } }}\sin \theta \left( {A\sin \phi \sin (t/R) - B\cos \phi \sin (t/R) - C\sin \phi \cos (t/R) + D\cos \phi \cos \left( {t/R} \right)} \right)<br />

<br /> \xi _\theta = rR\sqrt {1 + \left( {r/R} \right)^2 } \cos \theta \left( {A\sin \phi \sin \left( {t/R} \right) - B\cos \phi \sin \left( {t/R} \right) - C\sin \phi \cos \left( {t/R} \right) + D\cos \phi \cos \left( {t/R} \right)} \right)<br />

<br /> \xi _\phi = rR\sqrt {1 + \left( {r/R} \right)^2 } \sin \theta \left( {A\cos \phi \sin \left( {t/R} \right) + B\sin \phi \sin \left( {t/R} \right) - C\cos \phi \cos \left( {t/R} \right) - D\sin \phi \cos \left( {t/R} \right)} \right)<br />

These do satisfy the killing equation, but I feel like i"m missing something.

they only has 4 unknowns A, B, C, D not 10 like SO(1,4), also I don't understand how Teitelbohm and Henneaux got their lie algebra in their paper asymptotically anti de sitter spaces.

Any help will be much appreciated.
 
Physics news on Phys.org
To find the isometry group of AdS(n,m) consider its embedding in M(n,m+1) (Minkowski spacewith one extra time dimension). We can consider AdS as the set of points in M such that x2 = -R2.
Now consider the isometries of M that leave AdS invarient; it is not hard to show that this is O(n,m+1); hence O(n,m+1)< Iso(AdS(n,m));
As dim(O(n,m+1)) = (N2-N)/2 = (n+m)(n+m+1)/2; N = n+m+1
wehave that O(n,m+1) = Iso(adS(n,m)), Ads space is maximally symmetric.

To compute a basis for the lie algebra (in some coord's) use co-ord patch of the embeding of AdS and then compute which vector will be pushed forward to give all lin indep killing vectors in the embedding
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 20 ·
Replies
20
Views
2K
Replies
14
Views
1K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 47 ·
2
Replies
47
Views
7K
  • · Replies 8 ·
Replies
8
Views
2K