A weather rocket is launched straight upwards. The motor provides a constant acceleration for
18s, then the motor stops. The rocket altitude after 26s after launch is 5800m. What was the rocket's acceleration during the first 18 seconds?
[ tex ]x = x_0 + v_0 t + (1/2) a t^2
[ tex]v = v_0 + a t
The Attempt at a Solution
This answer doesn't seem right to me. I wasn't confident working it out.