- #1
JohnCy
- 6
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Homework Statement
A weather rocket is launched straight upwards. The motor provides a constant acceleration for
18s, then the motor stops. The rocket altitude after 26s after launch is 5800m. What was the rocket's acceleration during the first 18 seconds?
Homework Equations
[ tex ]x = x_0 + v_0 t + (1/2) a t^2
[/tex]
[ tex]v = v_0 + a t
[/tex]
The Attempt at a Solution
This answer doesn't seem right to me. I wasn't confident working it out.
5800=.5(a)(18)^2-(.5)(9.81)(8)^2
162a=5800+313.92
162a=6113.92
a=37.7