1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Kinematics: Angled Projectile Launch

  1. May 7, 2014 #1
    1. The problem statement, all variables and given/known data
    Determine the initial velocity of the projectile as it comes out of a cannon at a 20° angle.


    2. Relevant equations
    d = (Vi)(t) + 1/2(a)(t)^2


    3. The attempt at a solution
    I've split the question into both x and y components and solved for both using the equation above. Although I'm honestly unsure if I'm doing this correctly, would like some verification on my answer and point out any mistakes. Much appreciated! (Image below)

    http://imgur.com/pPWO2jG
     

    Attached Files:

    Last edited: May 7, 2014
  2. jcsd
  3. May 7, 2014 #2
    Hi SlooM,

    Are you sure v0y is 0 in the first equation that you've used to find t?
     
  4. May 7, 2014 #3
    Ah, I think that may have been my mistake which is kind of why I look at it and it doesn't make sense. I just put 0 for v0y and assumed it canceled that half of the equation. What would I put though, I feel like I don't have enough variables and am super confused.
     
  5. May 7, 2014 #4
    In addition to what Sunil has stated, there was also an algebra mistake at the end preventing you from getting the correct answer.

    [tex]\cos\theta = \frac{v_x}{v_i}[/tex]

    to

    [tex](cos\theta)v_x = v_i[/tex]

    instead of

    [tex]v_i =\frac{v_x}{cos\theta}[/tex]


    An easier way to do this problem it to remember that your x-component of velocity already has a cosine term in it. So once you solve for time you can simply say

    [tex]x(t) = V_otcos\theta[/tex]
     
    Last edited: May 7, 2014
  6. May 7, 2014 #5
    Oh! I can't believe I didn't see that. So I redid the algebra at the end and got 44.5 m/s but are my calculations in the previous x and y calculations correct? I keep second guessing myself :/

    I'm a rookie at physics but trying to improve. I appreciate all of your help and it means a lot.
     
  7. May 7, 2014 #6
    Hey we are all rookies :smile:

    We get two equations right?

    [itex]-1.5= v_{0y}t + \frac{g}{2}t^2[/itex]
    [itex]23=v_{0x}t[/itex]

    All we have to do is eliminate t. Moreover, v0x and v0y are related. So, you should be able to find v0x explicitly (and hence v0y).

    Could you check you answer again? I seem to be getting something different.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Kinematics: Angled Projectile Launch
Loading...