Projectile Angle Calculation: Finding Optimal Launch Angles for Accurate Hits

In summary, the problem involves shooting a cannon at a distant cliff with a height of 170m and a distance of 550m. The launch speed of the projectile is 110 m/s and wind resistance is ignored. To determine the angles at which the projectile should be shot to hit the target, the problem can be broken down into x and y components. Using the kinematics equations and the given information, the angle can be solved for using the arctan function.
  • #1
ericka141
8
0

Homework Statement


You shoot a cannon at a distant cliff. The cliff is 170m high and 550m away, with the launch speed of the projectile being 110 m/s. Wind resistance is ignored. At what angles, relative to the horizontal, should the projectile be shot to hit the target?

Hint: 1/cos2θ = 1+tan2θ


Homework Equations


Kinematics Equations:
vf=vi + a*t
d= vi*t + 1/2a*t^2
d= (vf^2-vi^2)/2a

The Attempt at a Solution


I've broken the problem up into x and y components:
vix= vixcos(θ)
dx= 550m (or vixcos(θ)*t)
ax= 0m/s^2

viy= viysin(θ)
dy= 170m (or viysin(θ)*t)
ay= -9.81m/s^2

I know how to find the maximum distance that a projectile travels when given the initial velocity (or the distance when given the initial velocity and the angle it's shot at) but I'm not sure how to find these angles. I'm not exactly sure where tan(θ) comes in. If somebody could help me with this that would be GREAT, this assignment is due tonight.
 
Physics news on Phys.org
  • #2
If you know x and y (or [itex]v_x[/itex] and [itex]v_y[/itex]), you can find the angle. Who is the man? Tan is the Man!

Recall SOH CAH TOA
 
  • #3
Then how would I use 1/cos2θ=1+tan2θ ??
 
  • #4
You don't. [itex]tan(\theta) = \frac{d_x}{d_y}[/itex]

Solve for [itex]\theta[/itex]
 
  • #5


I would approach this problem by first understanding the basic principles of projectile motion and the factors that affect it. From the given information, we know that the projectile has a constant initial velocity of 110 m/s and is affected by gravity (ay = -9.81 m/s^2). We also know that wind resistance is ignored.

To find the optimal launch angles for accurate hits, we need to consider the horizontal and vertical components of the projectile's motion. As you have correctly identified, the horizontal component (x) is affected only by the initial velocity (vix) and time (t) and is given by dx = vix * t. On the other hand, the vertical component (y) is affected by both the initial velocity (viy) and the acceleration due to gravity (ay), and is given by dy = viy * t + 1/2 * ay * t^2.

Now, to find the optimal launch angles, we need to consider two things: the maximum distance traveled by the projectile (which would result in hitting the target) and the angle at which this maximum distance occurs. Using the kinematics equations, we can calculate the maximum distance (dmax) as:

dmax = (vix^2 * sin(2θ)) / g

where g is the acceleration due to gravity, 9.81 m/s^2.

To find the angle at which this maximum distance occurs, we can use the hint provided: 1/cos2θ = 1 + tan2θ. This can be rearranged to solve for tan2θ, which will give us the angle at which the maximum distance occurs. Once we have this angle, we can solve for θ by taking the inverse tangent (tan^-1) of the result.

In summary, to find the optimal launch angles for accurate hits, we need to use the kinematics equations to calculate the maximum distance and then use the hint provided to solve for the angle at which this maximum distance occurs. I hope this helps and good luck with your assignment!
 

1. What is the angle of projectile?

The angle of projectile is the angle at which a projectile, such as a ball or bullet, is launched or thrown. It is measured from the horizontal direction and determines the trajectory of the projectile.

2. Why is the angle of projectile important?

The angle of projectile is important because it affects the distance and height the projectile will travel. A higher angle will result in a longer distance traveled, while a lower angle will result in a shorter distance but higher height.

3. How is the angle of projectile calculated?

The angle of projectile can be calculated using trigonometric functions such as sine, cosine, and tangent. The specific calculation will depend on the given parameters, such as initial velocity and height of launch.

4. What is the optimal angle of projectile for maximum distance?

The optimal angle of projectile for maximum distance is 45 degrees. This is because at this angle, the horizontal and vertical components of the initial velocity are equal, resulting in the longest distance traveled.

5. Can the angle of projectile affect other factors, such as air resistance?

Yes, the angle of projectile can affect other factors such as air resistance. A higher angle may result in a higher air resistance, causing the projectile to slow down and have a shorter distance traveled. This is why the optimal angle for maximum distance is not always 45 degrees in real-world situations.

Similar threads

  • Introductory Physics Homework Help
Replies
7
Views
2K
Replies
2
Views
2K
  • Introductory Physics Homework Help
2
Replies
36
Views
2K
  • Introductory Physics Homework Help
Replies
15
Views
7K
  • Introductory Physics Homework Help
Replies
4
Views
850
  • Introductory Physics Homework Help
Replies
8
Views
2K
  • Introductory Physics Homework Help
2
Replies
38
Views
1K
  • Introductory Physics Homework Help
Replies
19
Views
2K
  • Introductory Physics Homework Help
Replies
10
Views
3K
  • Introductory Physics Homework Help
Replies
15
Views
1K
Back
Top