A basketball player grabbing a rebound jumps 73.0 cm vertically. How much total time (ascent and descent, in ms) (a) does the player spend in the top 13.2 cm of this jump? (b) in the bottom 13.2 cm? (a) The formula I use is dx = Vot + 0.5at^2 Vo = 0 (at the top of the jump) dx = -.132 m a = -9.8 m/s^2 t = .164 I figure that the time spent going up and the time spent going down should be exactly the same. So 2t = .328 seconds (b) I use the formula Vf^2 = Vo^2 + 2adx Vf = 0 (at the top of the jump) dx = 0.73 m a = -9.8 m/s^2 Vo = 3.78 m/s With Vo, I use the formula dx = Vot + 0.5at^2 dx = .132 m a = -9.8 m/s^2 And I get t = .0366 So 2t = .0732 seconds Is everything correct?