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Kinematics help-determining distance traveled

  1. May 7, 2014 #1
    1. The problem statement, all variables and given/known data
    A particle starts from rest and travels in a straight line for 4 s. If the particle is accelerating at a constant rate, which of the following could be the distances traveled by the particle during each consecutive second?

    A) 10 m, 20 m, 30 m, 40 m

    B) 5 m, 15 m, 25 m, 35 m

    C) 5 m, 25 m, 125 m , 625 m

    D) 2 m, 4 m, 8 m, 16 m




    2. Relevant equations
    d = v0t + 1/2at2

    3. The attempt at a solution

    So I know from the information given in the question, we know the particle starts at rest, and v0 would equal 0. Because of this, we are left with:

    d = 1/2at2
    If I plug in 4, we'd get:
    d = 4a

    So based on this information, I thought the particle would be traveling 4 times more the distance per second. However, none of the answers choices above matched for how I thought about the equation that I'm left with. Any input would be appreciated!
     
  2. jcsd
  3. May 7, 2014 #2
    The distance traveled in a second is the difference between the position before and after the second goes by. So, for instance, between 3 and 4 seconds the particle travels from d3 = 1/2 a 32 to d4 = 1/2 a 42.
     
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