Kinematics -- particle acceleration and distance travelled 1. The problem statement, all variables and given/known data A particle moving at 10 m/s reverses its direction to move at 20 m/s in the opposite direction. If its acceleration is -10 m/s2, what is the total distance that it travels? A) 15 m B) 20 m C) 25 m D) 30 m 2. Relevant equations a = Δv/t v = Δx/t 3. The attempt at a solution In one direction: time = velocity/acceleration = 10/10 = 1 s velocity = distance/time = velocity * time = distance distance = 10 m/s * 1s = 10 m In the reverse direction: acceleration = velocity/accelertion; time = velocity/acceleration time = 20 m/s/10 m/s2 = 2 s velocity = distance/time; distance = velocity * time = 20 m/s * 2 = 40 m Distance traveled: 40 m + 10 m =50 m I realize my final answer did not come out to be any of the choices above but am not sure of any other correct way to approach this problem.