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GoGoGadget
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Kinematics -- particle acceleration and distance travelled
A particle moving at 10 m/s reverses its direction to move at 20 m/s in the opposite direction. If its acceleration is -10 m/s2, what is the total distance that it travels?
A) 15 m
B) 20 m
C) 25 m
D) 30 m
a = Δv/t
v = Δx/t
In one direction:
time = velocity/acceleration = 10/10 = 1 s
velocity = distance/time = velocity * time = distance
distance = 10 m/s * 1s = 10 m
In the reverse direction:
acceleration = velocity/accelertion; time = velocity/acceleration
time = 20 m/s/10 m/s2 = 2 s
velocity = distance/time; distance = velocity * time = 20 m/s * 2 = 40 m
Distance traveled:
40 m + 10 m =50 m
I realize my final answer did not come out to be any of the choices above but am not sure of any other correct way to approach this problem.
Homework Statement
A particle moving at 10 m/s reverses its direction to move at 20 m/s in the opposite direction. If its acceleration is -10 m/s2, what is the total distance that it travels?
A) 15 m
B) 20 m
C) 25 m
D) 30 m
Homework Equations
a = Δv/t
v = Δx/t
The Attempt at a Solution
In one direction:
time = velocity/acceleration = 10/10 = 1 s
velocity = distance/time = velocity * time = distance
distance = 10 m/s * 1s = 10 m
In the reverse direction:
acceleration = velocity/accelertion; time = velocity/acceleration
time = 20 m/s/10 m/s2 = 2 s
velocity = distance/time; distance = velocity * time = 20 m/s * 2 = 40 m
Distance traveled:
40 m + 10 m =50 m
I realize my final answer did not come out to be any of the choices above but am not sure of any other correct way to approach this problem.